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-5w^2+31w+28=0
a = -5; b = 31; c = +28;
Δ = b2-4ac
Δ = 312-4·(-5)·28
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-39}{2*-5}=\frac{-70}{-10} =+7 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+39}{2*-5}=\frac{8}{-10} =-4/5 $
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